Running Oracle DBCA(Database Confguration Assistance) remotely

There are two ways to create a new database on existing oracle db server. One is using 'CREATE DATABASE' sql statement[this is too long,hard for me]. Another is using DBCA(Database Confguration Assistance), GUI Base Program. This way is more easy and I choose this way:). One note here is DBCA need X to run and I want to remote login to db server and run dbca from ssh, so ssh need '-X' for X11 forward[assume that DISPLAY variable on server is set, if not try 'export DISPLAY=localhost:0.0' on the server].

[poj@fedev ~]$ ssh -X -l oracle 192.168.1.59
oracle@192.168.1.59's password:
Last login: Wed Apr 16 15:11:14 2008 from 192.168.1.122
/usr/X11R6/bin/xauth:  creating new authority file /home/oracle/.Xauthority
[oracle@k8n ~]$ cd /u01/app/oracle/product/10.1.0/db_1/bin
[oracle@k8n bin]$ dbca

Comments

Fixing sendmail take a long time to start

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Too many open files

Last week tomcat log file report many error about "Too many open files" when it has high traffic. Some in catalina_log say 2007-04-07 16:13:40 HttpProcessor[80][272] Starting background thread 2007-04-07 16:13:40 HttpConnector[80] accept: java.net.SocketException: Too many open files and here is from localhost_log 2007-04-07 16:13:40 StandardWrapperValve[myservlet]: Servlet.service() for servlet myservlet threw exception java.io.FileNotFoundException: /home/log/mylog_070407.log (Too many open files) This is because too many file descriptors're opened by tomcat. File descriptor can be limited in both system level and shell level. To check maximum number of fd in system type 'cat /proc/sys/fs/file-max'. In my case it is 65536(someone said it should set to 200000). Tomcat error when try to open socket number 272 so I think 65536 is ok for me for now. Anyway if u want to set it add 'fs.file-max = 200000' to /etc/sysctl.conf pnix@pnix-a7:~$ cat /proc/sys/fs/fil

using Class.getResource() load resource file in Eclipse

There are many ways to load resource file in java app. What sun recommended is using Class.getResource(" resource_name ") or Class.getResourceAsStream(" resource_name ") then you will get URL and InputStream respectively. If resource_name is specified without "/", it will be prepend with Class package. So resource file must be in same place[folder structure] as the Class. What I love to do is call getResource() with "/" and put resource file at the root of package. This way i can have separate resource folder. below is in Eclipse, 1. From Package explorer right click src folder->click import 2. In import dialog, Choose General->File System ->next 3. from directory:->Browse to your resource folder. 4. to folder:-> I add "resource" as a folder name under src folder. then click "Finish". In the code, load resource with this.getClass().getResource("/resource/buttons1.png") or this.getClass().getResourceAs

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